∫dx/(x的三次方+8)

解法如下：

原式=∫dx/(x^3+2^3)

=∫dx/(x+2)(x^2-2x+4)

=(1/12)∫1/(x+2)dx+∫[(-1/12)x+(1/3)]/(x^2-2x+4) dx

=(1/12)ln(x+2)-(1/24)∫d(x^2-2x+4)/(x^2-2x+4)+(1/4)∫1/(x^2-2x+4)dx

=(1/12)ln(x+2)-(1/24)ln(x^2-2x+4)+(1/4)∫1/[(x-1)^2+3] dx

=(1/12)ln(x+2)-(1/24)ln(x^2-2x+4)+(√3/12)∫ d[√3(x-1)/3] / 1+[√3(x-1)/3]^2

=(1/12)ln(x+2)-(1/24)ln(x^2-2x+4)+(√3/12)arctan[√3(x-1)/3]+ C

以上答案僅供參考，如有疑問可繼續(xù)追問！

口袋妖怪漆黑的魅影第8道館在哪

第七道館下來，要潛水才可以到達，。。。